3.18.47 \(\int \frac {(A+B x) (a^2+2 a b x+b^2 x^2)^{5/2}}{(d+e x)^3} \, dx\) [1747]

3.18.47.1 Optimal result
3.18.47.2 Mathematica [A] (verified)
3.18.47.3 Rubi [A] (verified)
3.18.47.4 Maple [A] (verified)
3.18.47.5 Fricas [B] (verification not implemented)
3.18.47.6 Sympy [F]
3.18.47.7 Maxima [F(-2)]
3.18.47.8 Giac [B] (verification not implemented)
3.18.47.9 Mupad [F(-1)]

3.18.47.1 Optimal result

Integrand size = 33, antiderivative size = 424 \[ \int \frac {(A+B x) \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=-\frac {10 b^2 (b d-a e)^2 (2 b B d-A b e-a B e) x \sqrt {a^2+2 a b x+b^2 x^2}}{e^6 (a+b x)}-\frac {(b d-a e)^5 (B d-A e) \sqrt {a^2+2 a b x+b^2 x^2}}{2 e^7 (a+b x) (d+e x)^2}+\frac {(b d-a e)^4 (6 b B d-5 A b e-a B e) \sqrt {a^2+2 a b x+b^2 x^2}}{e^7 (a+b x) (d+e x)}+\frac {5 b^3 (b d-a e) (3 b B d-A b e-2 a B e) (d+e x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}{2 e^7 (a+b x)}-\frac {b^4 (6 b B d-A b e-5 a B e) (d+e x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}{3 e^7 (a+b x)}+\frac {b^5 B (d+e x)^4 \sqrt {a^2+2 a b x+b^2 x^2}}{4 e^7 (a+b x)}+\frac {5 b (b d-a e)^3 (3 b B d-2 A b e-a B e) \sqrt {a^2+2 a b x+b^2 x^2} \log (d+e x)}{e^7 (a+b x)} \]

output
-10*b^2*(-a*e+b*d)^2*(-A*b*e-B*a*e+2*B*b*d)*x*((b*x+a)^2)^(1/2)/e^6/(b*x+a 
)-1/2*(-a*e+b*d)^5*(-A*e+B*d)*((b*x+a)^2)^(1/2)/e^7/(b*x+a)/(e*x+d)^2+(-a* 
e+b*d)^4*(-5*A*b*e-B*a*e+6*B*b*d)*((b*x+a)^2)^(1/2)/e^7/(b*x+a)/(e*x+d)+5/ 
2*b^3*(-a*e+b*d)*(-A*b*e-2*B*a*e+3*B*b*d)*(e*x+d)^2*((b*x+a)^2)^(1/2)/e^7/ 
(b*x+a)-1/3*b^4*(-A*b*e-5*B*a*e+6*B*b*d)*(e*x+d)^3*((b*x+a)^2)^(1/2)/e^7/( 
b*x+a)+1/4*b^5*B*(e*x+d)^4*((b*x+a)^2)^(1/2)/e^7/(b*x+a)+5*b*(-a*e+b*d)^3* 
(-2*A*b*e-B*a*e+3*B*b*d)*ln(e*x+d)*((b*x+a)^2)^(1/2)/e^7/(b*x+a)
 
3.18.47.2 Mathematica [A] (verified)

Time = 1.21 (sec) , antiderivative size = 501, normalized size of antiderivative = 1.18 \[ \int \frac {(A+B x) \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\frac {\sqrt {(a+b x)^2} \left (-6 a^5 e^5 (A e+B (d+2 e x))-30 a^4 b e^4 (A e (d+2 e x)-B d (3 d+4 e x))+60 a^3 b^2 e^3 \left (A d e (3 d+4 e x)+B \left (-5 d^3-4 d^2 e x+4 d e^2 x^2+2 e^3 x^3\right )\right )+60 a^2 b^3 e^2 \left (A e \left (-5 d^3-4 d^2 e x+4 d e^2 x^2+2 e^3 x^3\right )+B \left (7 d^4+2 d^3 e x-11 d^2 e^2 x^2-4 d e^3 x^3+e^4 x^4\right )\right )+10 a b^4 e \left (3 A e \left (7 d^4+2 d^3 e x-11 d^2 e^2 x^2-4 d e^3 x^3+e^4 x^4\right )+B \left (-27 d^5+6 d^4 e x+63 d^3 e^2 x^2+20 d^2 e^3 x^3-5 d e^4 x^4+2 e^5 x^5\right )\right )+b^5 \left (2 A e \left (-27 d^5+6 d^4 e x+63 d^3 e^2 x^2+20 d^2 e^3 x^3-5 d e^4 x^4+2 e^5 x^5\right )+3 B \left (22 d^6-16 d^5 e x-68 d^4 e^2 x^2-20 d^3 e^3 x^3+5 d^2 e^4 x^4-2 d e^5 x^5+e^6 x^6\right )\right )+60 b (b d-a e)^3 (3 b B d-2 A b e-a B e) (d+e x)^2 \log (d+e x)\right )}{12 e^7 (a+b x) (d+e x)^2} \]

input
Integrate[((A + B*x)*(a^2 + 2*a*b*x + b^2*x^2)^(5/2))/(d + e*x)^3,x]
 
output
(Sqrt[(a + b*x)^2]*(-6*a^5*e^5*(A*e + B*(d + 2*e*x)) - 30*a^4*b*e^4*(A*e*( 
d + 2*e*x) - B*d*(3*d + 4*e*x)) + 60*a^3*b^2*e^3*(A*d*e*(3*d + 4*e*x) + B* 
(-5*d^3 - 4*d^2*e*x + 4*d*e^2*x^2 + 2*e^3*x^3)) + 60*a^2*b^3*e^2*(A*e*(-5* 
d^3 - 4*d^2*e*x + 4*d*e^2*x^2 + 2*e^3*x^3) + B*(7*d^4 + 2*d^3*e*x - 11*d^2 
*e^2*x^2 - 4*d*e^3*x^3 + e^4*x^4)) + 10*a*b^4*e*(3*A*e*(7*d^4 + 2*d^3*e*x 
- 11*d^2*e^2*x^2 - 4*d*e^3*x^3 + e^4*x^4) + B*(-27*d^5 + 6*d^4*e*x + 63*d^ 
3*e^2*x^2 + 20*d^2*e^3*x^3 - 5*d*e^4*x^4 + 2*e^5*x^5)) + b^5*(2*A*e*(-27*d 
^5 + 6*d^4*e*x + 63*d^3*e^2*x^2 + 20*d^2*e^3*x^3 - 5*d*e^4*x^4 + 2*e^5*x^5 
) + 3*B*(22*d^6 - 16*d^5*e*x - 68*d^4*e^2*x^2 - 20*d^3*e^3*x^3 + 5*d^2*e^4 
*x^4 - 2*d*e^5*x^5 + e^6*x^6)) + 60*b*(b*d - a*e)^3*(3*b*B*d - 2*A*b*e - a 
*B*e)*(d + e*x)^2*Log[d + e*x]))/(12*e^7*(a + b*x)*(d + e*x)^2)
 
3.18.47.3 Rubi [A] (verified)

Time = 0.62 (sec) , antiderivative size = 263, normalized size of antiderivative = 0.62, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.121, Rules used = {1187, 27, 86, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{5/2} (A+B x)}{(d+e x)^3} \, dx\)

\(\Big \downarrow \) 1187

\(\displaystyle \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {b^5 (a+b x)^5 (A+B x)}{(d+e x)^3}dx}{b^5 (a+b x)}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {(a+b x)^5 (A+B x)}{(d+e x)^3}dx}{a+b x}\)

\(\Big \downarrow \) 86

\(\displaystyle \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \left (\frac {B (d+e x)^3 b^5}{e^6}+\frac {(-6 b B d+A b e+5 a B e) (d+e x)^2 b^4}{e^6}-\frac {5 (b d-a e) (-3 b B d+A b e+2 a B e) (d+e x) b^3}{e^6}+\frac {10 (b d-a e)^2 (-2 b B d+A b e+a B e) b^2}{e^6}-\frac {5 (b d-a e)^3 (-3 b B d+2 A b e+a B e) b}{e^6 (d+e x)}+\frac {(a e-b d)^4 (-6 b B d+5 A b e+a B e)}{e^6 (d+e x)^2}+\frac {(a e-b d)^5 (A e-B d)}{e^6 (d+e x)^3}\right )dx}{a+b x}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {\sqrt {a^2+2 a b x+b^2 x^2} \left (-\frac {b^4 (d+e x)^3 (-5 a B e-A b e+6 b B d)}{3 e^7}+\frac {5 b^3 (d+e x)^2 (b d-a e) (-2 a B e-A b e+3 b B d)}{2 e^7}-\frac {10 b^2 x (b d-a e)^2 (-a B e-A b e+2 b B d)}{e^6}+\frac {(b d-a e)^4 (-a B e-5 A b e+6 b B d)}{e^7 (d+e x)}-\frac {(b d-a e)^5 (B d-A e)}{2 e^7 (d+e x)^2}+\frac {5 b (b d-a e)^3 \log (d+e x) (-a B e-2 A b e+3 b B d)}{e^7}+\frac {b^5 B (d+e x)^4}{4 e^7}\right )}{a+b x}\)

input
Int[((A + B*x)*(a^2 + 2*a*b*x + b^2*x^2)^(5/2))/(d + e*x)^3,x]
 
output
(Sqrt[a^2 + 2*a*b*x + b^2*x^2]*((-10*b^2*(b*d - a*e)^2*(2*b*B*d - A*b*e - 
a*B*e)*x)/e^6 - ((b*d - a*e)^5*(B*d - A*e))/(2*e^7*(d + e*x)^2) + ((b*d - 
a*e)^4*(6*b*B*d - 5*A*b*e - a*B*e))/(e^7*(d + e*x)) + (5*b^3*(b*d - a*e)*( 
3*b*B*d - A*b*e - 2*a*B*e)*(d + e*x)^2)/(2*e^7) - (b^4*(6*b*B*d - A*b*e - 
5*a*B*e)*(d + e*x)^3)/(3*e^7) + (b^5*B*(d + e*x)^4)/(4*e^7) + (5*b*(b*d - 
a*e)^3*(3*b*B*d - 2*A*b*e - a*B*e)*Log[d + e*x])/e^7))/(a + b*x)
 

3.18.47.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 86
Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_ 
.), x_] :> Int[ExpandIntegrand[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; 
 FreeQ[{a, b, c, d, e, f, n}, x] && ((ILtQ[n, 0] && ILtQ[p, 0]) || EqQ[p, 1 
] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p 
+ 1, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))
 

rule 1187
Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))^(n_.)*((a_) + (b_.)*(x_ 
) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(a + b*x + c*x^2)^FracPart[p]/(c^ 
IntPart[p]*(b/2 + c*x)^(2*FracPart[p]))   Int[(d + e*x)^m*(f + g*x)^n*(b/2 
+ c*x)^(2*p), x], x] /; FreeQ[{a, b, c, d, e, f, g, m, n, p}, x] && EqQ[b^2 
 - 4*a*c, 0] &&  !IntegerQ[p]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 
3.18.47.4 Maple [A] (verified)

Time = 0.50 (sec) , antiderivative size = 661, normalized size of antiderivative = 1.56

method result size
risch \(\frac {\sqrt {\left (b x +a \right )^{2}}\, b^{2} \left (\frac {1}{4} b^{3} B \,x^{4} e^{3}+\frac {1}{3} A \,b^{3} e^{3} x^{3}+\frac {5}{3} B a \,b^{2} e^{3} x^{3}-B \,b^{3} d \,e^{2} x^{3}+\frac {5}{2} A a \,b^{2} e^{3} x^{2}-\frac {3}{2} A \,b^{3} d \,e^{2} x^{2}+5 B \,a^{2} b \,e^{3} x^{2}-\frac {15}{2} B a \,b^{2} d \,e^{2} x^{2}+3 B \,b^{3} d^{2} e \,x^{2}+10 A \,a^{2} b \,e^{3} x -15 A a \,b^{2} d \,e^{2} x +6 A \,b^{3} d^{2} e x +10 B \,e^{3} a^{3} x -30 B \,a^{2} b d \,e^{2} x +30 B a \,b^{2} d^{2} e x -10 B \,b^{3} d^{3} x \right )}{\left (b x +a \right ) e^{6}}+\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (\left (-5 A \,a^{4} b \,e^{5}+20 A \,a^{3} b^{2} d \,e^{4}-30 A \,a^{2} b^{3} d^{2} e^{3}+20 A a \,b^{4} d^{3} e^{2}-5 A \,b^{5} d^{4} e -B \,a^{5} e^{5}+10 B \,a^{4} b d \,e^{4}-30 B \,a^{3} b^{2} d^{2} e^{3}+40 B \,a^{2} b^{3} d^{3} e^{2}-25 B a \,b^{4} d^{4} e +6 B \,b^{5} d^{5}\right ) x -\frac {A \,a^{5} e^{6}+5 A \,a^{4} b d \,e^{5}-30 A \,a^{3} b^{2} d^{2} e^{4}+50 A \,a^{2} b^{3} d^{3} e^{3}-35 A a \,b^{4} d^{4} e^{2}+9 A \,b^{5} d^{5} e +B \,a^{5} d \,e^{5}-15 B \,a^{4} b \,d^{2} e^{4}+50 B \,a^{3} b^{2} d^{3} e^{3}-70 B \,a^{2} b^{3} d^{4} e^{2}+45 B a \,b^{4} d^{5} e -11 B \,b^{5} d^{6}}{2 e}\right )}{\left (b x +a \right ) e^{6} \left (e x +d \right )^{2}}+\frac {5 \sqrt {\left (b x +a \right )^{2}}\, b \left (2 A \,a^{3} b \,e^{4}-6 A \,a^{2} b^{2} d \,e^{3}+6 A a \,b^{3} d^{2} e^{2}-2 A \,b^{4} d^{3} e +B \,a^{4} e^{4}-6 B \,a^{3} b d \,e^{3}+12 B \,a^{2} b^{2} d^{2} e^{2}-10 B a \,b^{3} d^{3} e +3 b^{4} B \,d^{4}\right ) \ln \left (e x +d \right )}{\left (b x +a \right ) e^{7}}\) \(661\)
default \(\text {Expression too large to display}\) \(1205\)

input
int((B*x+A)*(b^2*x^2+2*a*b*x+a^2)^(5/2)/(e*x+d)^3,x,method=_RETURNVERBOSE)
 
output
((b*x+a)^2)^(1/2)/(b*x+a)*b^2/e^6*(1/4*b^3*B*x^4*e^3+1/3*A*b^3*e^3*x^3+5/3 
*B*a*b^2*e^3*x^3-B*b^3*d*e^2*x^3+5/2*A*a*b^2*e^3*x^2-3/2*A*b^3*d*e^2*x^2+5 
*B*a^2*b*e^3*x^2-15/2*B*a*b^2*d*e^2*x^2+3*B*b^3*d^2*e*x^2+10*A*a^2*b*e^3*x 
-15*A*a*b^2*d*e^2*x+6*A*b^3*d^2*e*x+10*B*e^3*a^3*x-30*B*a^2*b*d*e^2*x+30*B 
*a*b^2*d^2*e*x-10*B*b^3*d^3*x)+((b*x+a)^2)^(1/2)/(b*x+a)*((-5*A*a^4*b*e^5+ 
20*A*a^3*b^2*d*e^4-30*A*a^2*b^3*d^2*e^3+20*A*a*b^4*d^3*e^2-5*A*b^5*d^4*e-B 
*a^5*e^5+10*B*a^4*b*d*e^4-30*B*a^3*b^2*d^2*e^3+40*B*a^2*b^3*d^3*e^2-25*B*a 
*b^4*d^4*e+6*B*b^5*d^5)*x-1/2*(A*a^5*e^6+5*A*a^4*b*d*e^5-30*A*a^3*b^2*d^2* 
e^4+50*A*a^2*b^3*d^3*e^3-35*A*a*b^4*d^4*e^2+9*A*b^5*d^5*e+B*a^5*d*e^5-15*B 
*a^4*b*d^2*e^4+50*B*a^3*b^2*d^3*e^3-70*B*a^2*b^3*d^4*e^2+45*B*a*b^4*d^5*e- 
11*B*b^5*d^6)/e)/e^6/(e*x+d)^2+5*((b*x+a)^2)^(1/2)/(b*x+a)*b/e^7*(2*A*a^3* 
b*e^4-6*A*a^2*b^2*d*e^3+6*A*a*b^3*d^2*e^2-2*A*b^4*d^3*e+B*a^4*e^4-6*B*a^3* 
b*d*e^3+12*B*a^2*b^2*d^2*e^2-10*B*a*b^3*d^3*e+3*B*b^4*d^4)*ln(e*x+d)
 
3.18.47.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 871 vs. \(2 (339) = 678\).

Time = 0.36 (sec) , antiderivative size = 871, normalized size of antiderivative = 2.05 \[ \int \frac {(A+B x) \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\frac {3 \, B b^{5} e^{6} x^{6} + 66 \, B b^{5} d^{6} - 6 \, A a^{5} e^{6} - 54 \, {\left (5 \, B a b^{4} + A b^{5}\right )} d^{5} e + 210 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} d^{4} e^{2} - 300 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} d^{3} e^{3} + 90 \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} d^{2} e^{4} - 6 \, {\left (B a^{5} + 5 \, A a^{4} b\right )} d e^{5} - 2 \, {\left (3 \, B b^{5} d e^{5} - 2 \, {\left (5 \, B a b^{4} + A b^{5}\right )} e^{6}\right )} x^{5} + 5 \, {\left (3 \, B b^{5} d^{2} e^{4} - 2 \, {\left (5 \, B a b^{4} + A b^{5}\right )} d e^{5} + 6 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} e^{6}\right )} x^{4} - 20 \, {\left (3 \, B b^{5} d^{3} e^{3} - 2 \, {\left (5 \, B a b^{4} + A b^{5}\right )} d^{2} e^{4} + 6 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} d e^{5} - 6 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} e^{6}\right )} x^{3} - 6 \, {\left (34 \, B b^{5} d^{4} e^{2} - 21 \, {\left (5 \, B a b^{4} + A b^{5}\right )} d^{3} e^{3} + 55 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} d^{2} e^{4} - 40 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} d e^{5}\right )} x^{2} - 12 \, {\left (4 \, B b^{5} d^{5} e - {\left (5 \, B a b^{4} + A b^{5}\right )} d^{4} e^{2} - 5 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} d^{3} e^{3} + 20 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} d^{2} e^{4} - 10 \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} d e^{5} + {\left (B a^{5} + 5 \, A a^{4} b\right )} e^{6}\right )} x + 60 \, {\left (3 \, B b^{5} d^{6} - 2 \, {\left (5 \, B a b^{4} + A b^{5}\right )} d^{5} e + 6 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} d^{4} e^{2} - 6 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} d^{3} e^{3} + {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} d^{2} e^{4} + {\left (3 \, B b^{5} d^{4} e^{2} - 2 \, {\left (5 \, B a b^{4} + A b^{5}\right )} d^{3} e^{3} + 6 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} d^{2} e^{4} - 6 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} d e^{5} + {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} e^{6}\right )} x^{2} + 2 \, {\left (3 \, B b^{5} d^{5} e - 2 \, {\left (5 \, B a b^{4} + A b^{5}\right )} d^{4} e^{2} + 6 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} d^{3} e^{3} - 6 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} d^{2} e^{4} + {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} d e^{5}\right )} x\right )} \log \left (e x + d\right )}{12 \, {\left (e^{9} x^{2} + 2 \, d e^{8} x + d^{2} e^{7}\right )}} \]

input
integrate((B*x+A)*(b^2*x^2+2*a*b*x+a^2)^(5/2)/(e*x+d)^3,x, algorithm="fric 
as")
 
output
1/12*(3*B*b^5*e^6*x^6 + 66*B*b^5*d^6 - 6*A*a^5*e^6 - 54*(5*B*a*b^4 + A*b^5 
)*d^5*e + 210*(2*B*a^2*b^3 + A*a*b^4)*d^4*e^2 - 300*(B*a^3*b^2 + A*a^2*b^3 
)*d^3*e^3 + 90*(B*a^4*b + 2*A*a^3*b^2)*d^2*e^4 - 6*(B*a^5 + 5*A*a^4*b)*d*e 
^5 - 2*(3*B*b^5*d*e^5 - 2*(5*B*a*b^4 + A*b^5)*e^6)*x^5 + 5*(3*B*b^5*d^2*e^ 
4 - 2*(5*B*a*b^4 + A*b^5)*d*e^5 + 6*(2*B*a^2*b^3 + A*a*b^4)*e^6)*x^4 - 20* 
(3*B*b^5*d^3*e^3 - 2*(5*B*a*b^4 + A*b^5)*d^2*e^4 + 6*(2*B*a^2*b^3 + A*a*b^ 
4)*d*e^5 - 6*(B*a^3*b^2 + A*a^2*b^3)*e^6)*x^3 - 6*(34*B*b^5*d^4*e^2 - 21*( 
5*B*a*b^4 + A*b^5)*d^3*e^3 + 55*(2*B*a^2*b^3 + A*a*b^4)*d^2*e^4 - 40*(B*a^ 
3*b^2 + A*a^2*b^3)*d*e^5)*x^2 - 12*(4*B*b^5*d^5*e - (5*B*a*b^4 + A*b^5)*d^ 
4*e^2 - 5*(2*B*a^2*b^3 + A*a*b^4)*d^3*e^3 + 20*(B*a^3*b^2 + A*a^2*b^3)*d^2 
*e^4 - 10*(B*a^4*b + 2*A*a^3*b^2)*d*e^5 + (B*a^5 + 5*A*a^4*b)*e^6)*x + 60* 
(3*B*b^5*d^6 - 2*(5*B*a*b^4 + A*b^5)*d^5*e + 6*(2*B*a^2*b^3 + A*a*b^4)*d^4 
*e^2 - 6*(B*a^3*b^2 + A*a^2*b^3)*d^3*e^3 + (B*a^4*b + 2*A*a^3*b^2)*d^2*e^4 
 + (3*B*b^5*d^4*e^2 - 2*(5*B*a*b^4 + A*b^5)*d^3*e^3 + 6*(2*B*a^2*b^3 + A*a 
*b^4)*d^2*e^4 - 6*(B*a^3*b^2 + A*a^2*b^3)*d*e^5 + (B*a^4*b + 2*A*a^3*b^2)* 
e^6)*x^2 + 2*(3*B*b^5*d^5*e - 2*(5*B*a*b^4 + A*b^5)*d^4*e^2 + 6*(2*B*a^2*b 
^3 + A*a*b^4)*d^3*e^3 - 6*(B*a^3*b^2 + A*a^2*b^3)*d^2*e^4 + (B*a^4*b + 2*A 
*a^3*b^2)*d*e^5)*x)*log(e*x + d))/(e^9*x^2 + 2*d*e^8*x + d^2*e^7)
 
3.18.47.6 Sympy [F]

\[ \int \frac {(A+B x) \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\int \frac {\left (A + B x\right ) \left (\left (a + b x\right )^{2}\right )^{\frac {5}{2}}}{\left (d + e x\right )^{3}}\, dx \]

input
integrate((B*x+A)*(b**2*x**2+2*a*b*x+a**2)**(5/2)/(e*x+d)**3,x)
 
output
Integral((A + B*x)*((a + b*x)**2)**(5/2)/(d + e*x)**3, x)
 
3.18.47.7 Maxima [F(-2)]

Exception generated. \[ \int \frac {(A+B x) \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\text {Exception raised: ValueError} \]

input
integrate((B*x+A)*(b^2*x^2+2*a*b*x+a^2)^(5/2)/(e*x+d)^3,x, algorithm="maxi 
ma")
 
output
Exception raised: ValueError >> Computation failed since Maxima requested 
additional constraints; using the 'assume' command before evaluation *may* 
 help (example of legal syntax is 'assume(a*e-b*d>0)', see `assume?` for m 
ore detail
 
3.18.47.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 924 vs. \(2 (339) = 678\).

Time = 0.28 (sec) , antiderivative size = 924, normalized size of antiderivative = 2.18 \[ \int \frac {(A+B x) \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\text {Too large to display} \]

input
integrate((B*x+A)*(b^2*x^2+2*a*b*x+a^2)^(5/2)/(e*x+d)^3,x, algorithm="giac 
")
 
output
5*(3*B*b^5*d^4*sgn(b*x + a) - 10*B*a*b^4*d^3*e*sgn(b*x + a) - 2*A*b^5*d^3* 
e*sgn(b*x + a) + 12*B*a^2*b^3*d^2*e^2*sgn(b*x + a) + 6*A*a*b^4*d^2*e^2*sgn 
(b*x + a) - 6*B*a^3*b^2*d*e^3*sgn(b*x + a) - 6*A*a^2*b^3*d*e^3*sgn(b*x + a 
) + B*a^4*b*e^4*sgn(b*x + a) + 2*A*a^3*b^2*e^4*sgn(b*x + a))*log(abs(e*x + 
 d))/e^7 + 1/2*(11*B*b^5*d^6*sgn(b*x + a) - 45*B*a*b^4*d^5*e*sgn(b*x + a) 
- 9*A*b^5*d^5*e*sgn(b*x + a) + 70*B*a^2*b^3*d^4*e^2*sgn(b*x + a) + 35*A*a* 
b^4*d^4*e^2*sgn(b*x + a) - 50*B*a^3*b^2*d^3*e^3*sgn(b*x + a) - 50*A*a^2*b^ 
3*d^3*e^3*sgn(b*x + a) + 15*B*a^4*b*d^2*e^4*sgn(b*x + a) + 30*A*a^3*b^2*d^ 
2*e^4*sgn(b*x + a) - B*a^5*d*e^5*sgn(b*x + a) - 5*A*a^4*b*d*e^5*sgn(b*x + 
a) - A*a^5*e^6*sgn(b*x + a) + 2*(6*B*b^5*d^5*e*sgn(b*x + a) - 25*B*a*b^4*d 
^4*e^2*sgn(b*x + a) - 5*A*b^5*d^4*e^2*sgn(b*x + a) + 40*B*a^2*b^3*d^3*e^3* 
sgn(b*x + a) + 20*A*a*b^4*d^3*e^3*sgn(b*x + a) - 30*B*a^3*b^2*d^2*e^4*sgn( 
b*x + a) - 30*A*a^2*b^3*d^2*e^4*sgn(b*x + a) + 10*B*a^4*b*d*e^5*sgn(b*x + 
a) + 20*A*a^3*b^2*d*e^5*sgn(b*x + a) - B*a^5*e^6*sgn(b*x + a) - 5*A*a^4*b* 
e^6*sgn(b*x + a))*x)/((e*x + d)^2*e^7) + 1/12*(3*B*b^5*e^9*x^4*sgn(b*x + a 
) - 12*B*b^5*d*e^8*x^3*sgn(b*x + a) + 20*B*a*b^4*e^9*x^3*sgn(b*x + a) + 4* 
A*b^5*e^9*x^3*sgn(b*x + a) + 36*B*b^5*d^2*e^7*x^2*sgn(b*x + a) - 90*B*a*b^ 
4*d*e^8*x^2*sgn(b*x + a) - 18*A*b^5*d*e^8*x^2*sgn(b*x + a) + 60*B*a^2*b^3* 
e^9*x^2*sgn(b*x + a) + 30*A*a*b^4*e^9*x^2*sgn(b*x + a) - 120*B*b^5*d^3*e^6 
*x*sgn(b*x + a) + 360*B*a*b^4*d^2*e^7*x*sgn(b*x + a) + 72*A*b^5*d^2*e^7...
 
3.18.47.9 Mupad [F(-1)]

Timed out. \[ \int \frac {(A+B x) \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\int \frac {\left (A+B\,x\right )\,{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2}}{{\left (d+e\,x\right )}^3} \,d x \]

input
int(((A + B*x)*(a^2 + b^2*x^2 + 2*a*b*x)^(5/2))/(d + e*x)^3,x)
 
output
int(((A + B*x)*(a^2 + b^2*x^2 + 2*a*b*x)^(5/2))/(d + e*x)^3, x)